Added Union-Find algorithm

main
oabrivard 2 years ago
parent 79a3989812
commit 9b5259c192

@ -0,0 +1,45 @@
package algo
type Subset struct {
parent string
rank int
}
// find is a recursive function that finds the root of the subset that element 'e' belongs to.
// It uses path compression technique to optimize future find operations.
// The subsets parameter is a map that stores the subsets with their parent information.
// The e parameter is the element for which the root is to be found.
// The function returns the root of the subset that 'e' belongs to.
// see https://ondrej-kvasnovsky-2.gitbook.io/algorithms/finding/union-find-algorithms
// or https://jojozhuang.github.io/algorithm/algorithm-union-find/
func find(subsets map[string]*Subset, e string) string {
// find root and make root as parent of e
// (path compression)
if subsets[e].parent != e {
subsets[e].parent = find(subsets, subsets[e].parent)
}
return subsets[e].parent
}
// Union merges two subsets in the union-find data structure.
// It takes a map of subsets, and the names of the two subsets to be merged.
// The function finds the root of each subset and performs the union operation based on the rank of the subsets.
func Union(subsets map[string]*Subset, x, y string) {
xroot := find(subsets, x)
yroot := find(subsets, y)
// Attach smaller rank tree under root of high
// rank tree (Union by Rank)
if subsets[xroot].rank < subsets[yroot].rank {
subsets[xroot].parent = yroot
} else {
if subsets[xroot].rank > subsets[yroot].rank {
subsets[yroot].parent = xroot
} else {
// If ranks are same, then make one as root and
// increment its rank by one
subsets[yroot].parent = xroot
subsets[xroot].rank++
}
}
}

@ -0,0 +1,111 @@
package algo
import (
"testing"
)
func TestFind(t *testing.T) {
subsets := map[string]*Subset{
"a": {parent: "a"},
"b": {parent: "a"},
"c": {parent: "b"},
"d": {parent: "c"},
}
tests := []struct {
name string
subsets map[string]*Subset
element string
expected string
}{
{
name: "element is root",
subsets: subsets,
element: "a",
expected: "a",
},
{
name: "element has parent",
subsets: subsets,
element: "b",
expected: "a",
},
{
name: "element has grandparent",
subsets: subsets,
element: "c",
expected: "a",
},
{
name: "element has great-grandparent",
subsets: subsets,
element: "d",
expected: "a",
},
}
for _, tt := range tests {
t.Run(tt.name, func(t *testing.T) {
got := find(tt.subsets, tt.element)
if got != tt.expected {
t.Errorf("find() = %v, want %v", got, tt.expected)
}
})
}
}
func TestUnion(t *testing.T) {
subsets := map[string]*Subset{
"a": {parent: "a"},
"b": {parent: "a"},
"c": {parent: "b"},
"d": {parent: "c"},
}
tests := []struct {
name string
subsets map[string]*Subset
x string
y string
expectedXRoot string
}{
{
name: "x and y are already in the same subset",
subsets: subsets,
x: "a",
y: "b",
expectedXRoot: "a",
},
{
name: "x and y are in different subsets",
subsets: subsets,
x: "b",
y: "c",
expectedXRoot: "a",
},
{
name: "x and y are in different subsets with different ranks",
subsets: subsets,
x: "c",
y: "d",
expectedXRoot: "a",
},
{
name: "x and y are in different subsets with same rank",
subsets: subsets,
x: "a",
y: "d",
expectedXRoot: "a",
},
}
for _, tt := range tests {
t.Run(tt.name, func(t *testing.T) {
Union(tt.subsets, tt.x, tt.y)
got := find(tt.subsets, tt.x)
if got != tt.expectedXRoot {
t.Errorf("Union() failed, got x root = %v, want %v", got, tt.expectedXRoot)
}
})
}
}
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